Factorise a2-b2-c2+2bc
WebOct 20, 2012 · ( a + b + c)2 - (a - b - c)2 + 4b2 - 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ac - ( a2 + b2 + c2 - 2ab - 2bc - 2ac) + 4b2 - 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ac - a2 - b2 - c2 + 2ab + 2bc + 2ac +4b2 - 4c2 = 4ab + 4bc + 4ac + 4b2 - 4c2 =4 ( ab + bc + ac + b2 - c2 ) ANSWER = 4 ( ab + bc + ac + b2 - c2 ) Was this answer helpful? 4 View Full Answer Weba^2 + b^2 + 2bc - 2ca - 2ab = (a^2 - 2ab + b^2) + 2bc - 2ca then = (a - b)^2 - 2c(a - b) = (a - b)[(a - b) - 2c)] = (a - b)(a - b - 2c)
Factorise a2-b2-c2+2bc
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WebSolution a 2 + b 2 - c 2 - d 2 + 2ab - 2cd = ( a 2 + b 2 + 2ab ) - ( c 2 + d 2 + 2cd ) = ( a + b ) 2 - ( c + d ) 2 = [ ( a + b ) - ( c + d )] [ ( a + b ) + ( c + d )] [∵ a 2 - b 2 = ( a + b ) ( a - b )] = ( a + b - c - d ) ( a + b + c + d ) Concept: Method of Factorisation : Difference of Two Squares Is there an error in this question or solution? WebJan 25, 2024 · a2 + b2 + c2ab-bc- ca = 0. Multiply both sides with 2, we get. 2(a2 + b2 + c2ab-bc-ca) = 0. → 2a2 + 2b2 +2c2 - 2ab - 2bc - 2ca = → a2 + a2 + b2 + b2 + c2 + c2- 2ab - 2bc2ca0 (a2 - 2ab + b2) + (b2-2bc + c2) + (c2 - 2ca + a2) = 0 (a - b)2 + (b − c)2 + (ca)2 = 0. Since the sum of squares is zero, it means each term should be zero.
WebSep 20, 2016 · Factorise-a2-b2+2bc-c2 - 761991. Given : The algebraic expression is, a²-b²+2bc-c² To find : The factorisation of the given algebraic expression. Solution : We can simply solve this mathematical problem by … Weba2+b2+c2 Formula. The a 2 + b 2 + c 2 formula is used to find the sum of squares of three numbers without actually calculating the squares. a 2 + b 2 + c 2 formula is one of the …
Web(a+b+c)^2 identity formula expansion proof (a+b+c)2=a2+b2+c2+2ab+2bc+2ca verify example prove compute ow to factorise using the identity (a+b+c)^2=a^2+b^2+c^... WebSep 13, 2011 · It can be calculated using a variety of methods - Pythagoras theorem : A2 + B2 = C2, where A and B are the sides adjacent to the right angle, and C is the hypotenuse. The square of A plus the...
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WebFactor 9a^2-b^2. 9a2 − b2 9 a 2 - b 2. Rewrite 9a2 9 a 2 as (3a)2 ( 3 a) 2. (3a)2 − b2 ( 3 a) 2 - b 2. Since both terms are perfect squares, factor using the difference of squares … empire strikes back promotional posterWebJul 31, 2011 · Boards. CBSE. Class 1; Class 2; Class 3; Class 4; Class 5; Class 6; Class 7; Class 8; Class 9; Class 10; Class 11 Science; Class 11 Commerce; Class 12 Science; Class ... empire strikes back mystery minis targetWeb= a 2 - (b 2 - 2bc + c 2) Using identity a 2 - 2ab + b 2 = (a - b) 2 = a 2 - (b - c) 2. Using identity a 2 - b 2 = (a + b)(a - b) = (a + b - c)(a - (b - c)) = (a + b - c)(a - b + c) ∴ a 2 - b 2 … empire strikes back original logoWebClick here👆to get an answer to your question ️ Factorise: a^2 - 2ab + b^2 - c^2 empire strikes back palpatineWebJun 7, 2024 · Factorize: a^2 + b^2 - 2ba + 2bc - 2ca - 4026992. the area covered by a fire increases by 17% each hour currently the fire covers an area of 32m^2 if the fire … dr. arvind chaudhry spokaneWebOn the other hand, the space of solutions (a,b) to any equation of the form 0 = p (a,b)q (a,b) where p,q are degree- 1 is a union of two (usually intersecting) linear subspaces in … empire strikes back x ratedWebTo prove this equation non-negative, you will have to convert the equation in terms of perfect square form containing a,b and c. Now, a²+b²+c²-ab-bc-ca = ½ • ( 2a²+2b²+2c²-2ab-2bc -2ca ) = ½ • ( ... Three line equations with cyclically permuted coefficients empire strikes back subtitles