WebAnswer (1 of 3): At STP , 1 mol Cl2 gas has volume 22.4 L Molar mass Cl2 = 35.5*2 = 71 g/mol Mol Cl2 in 0.71 g = 0.71 g / 71 g/mol = 0.01 mol Volume of 0.01 mol Cl2 at STP … WebScience Chemistry If 25.0 mL of chlorine gas (Cl2) at STP and 15.0 mL of ethyne gas (CHCH) at STP are reacted together to form tetrachloroethane (CHCI2CHCI2), how many moles of tetrachloroethane are formed? 2 Cl2 (g) + CHCH (g) CHC1»CHC12 (g) а. 8.93 х 10-4 mol O b. 5.58 x 10-4 mol O c. 1.12 x 103 mol O d. 6.70 x 10-4 mol e. 0.558 mol
Answered: At STP, how many moles are in these… bartleby
Web31 jul. 2024 · Calculate the density of chlorine gas (Cl2) at STP. Assume ideal conditions.PV=nRTn=m/M (n=moles ; m=mass ; M=molar mass)PV=(m/M) ... Web16 mei 2024 · All you need to know is at STP 1 mole of an ideal gas = 22.4 liters. Thus, 11.2 L x 1 mol/22.4 L = 0.5 moles 0.5 moles x 32 g/mole = 16 g. You were correct. The previous answer has several errors. First , n = 0.499 =0.5 mokes, not 0.0446. Second error is that molar mass of O2 is 32 g, not 16 g. Upvote • 1 Downvote Add comment Report simpsons season 14 large marge
9.3 Stoichiometry of Gaseous Substances, Mixtures, and Reactions
Web13 nov. 2024 · Since the reaction takes place at STP (standard temperature and pressure), we know that 1 mole of an ideal gas equals 22.4 liters. For this problem, we don't even … Webare there in 15 L at STP? 1.3.0 moles 2.0.50 moles 3.5.0 moles 4.1.0 moles 5.0.67 moles correct Explanation: At STP, 1 mole of an ideal gas has a volume of 22.4 L; i.e., 22.4 L mol. (15 L) mol 22.4 L = 0.67 mol Mlib041147 007 10.0points What is the final volume if 10 L methane reacts completely with 20 L oxygen WebHow many grams of water will be produced when 24.0 grams of calcium carbonate reacts with 10.0 grams of hydrochloric acid? CaCO3(s) + 2HCl(aq) arrow CaCl2(aq) + H2O(l) + … razor energy corp rts