WebA simple React Native component that takes an array of data and renders a SectionList with alphabetically (or custom) sorted data. ... The component handles all this logic internally. You can also provide an array of characters to sort your sections in a custom order. ... if we wanted to sort alphabetically in-reverse, we could do: const ... WebDec 28, 2024 · 2 Your sort compare function is comparing the length of name which will sort the array by the length of the name. Change your sorter for name to below. sorter: (a, b) => { if (a.name < b.name) { return -1; } if (a.name > b.name) { return 1; } return 0; }, You also need to change sorter for address.
Natural sort of alphanumerical strings in JavaScript
WebJul 27, 2024 · var Comparison_sort = this.Comparison.sort (function (a, b) { if (a.key == b.key) return 0; if (a.key == 'None') return -1; if (b.key == 'None') return 1; if (a.key < b.key) return -1; if (a.key > b.key) return 1; return 0; }); tells "do a regular sort, except if the key is none which means it must go first." Share Follow WebJan 29, 2024 · The second invocation to data.sort () (without custom sort function logic) is overwriting the initial sort logic which is why your custom logic of comparing a.userID > b.userId is not achieving any expected results. @gaiazov Answer below a.title - b.title answers the sort-by-title question. – Tobiah Rex Jan 29, 2024 at 0:02 cultural arranged marriage visa
How to Sort an Array of Objects in React and Then Render Them?
WebMar 5, 2024 · The right way is first to do the copy of the bands array, sort it and then call setData with this array. So, just adding the spread operator to copy array should solve the … WebJun 8, 2012 · By customizing the sort logic of the compare function and passing it to the sort () method the keys above get sorted correctly: sorted.sort (function (a, b) { a = parseInt (get_between (a, 'canvas_', '_')); b = parseInt (get_between (b, 'canvas_', '_')); if (a > b) { return 1; } if (b > a) { return -1; } return 0; }); WebJan 25, 2012 · myArray.sort ( function (a, b) { if (a.toLowerCase () < b.toLowerCase ()) return -1; if (a.toLowerCase () > b.toLowerCase ()) return 1; return 0; } ); EDIT: Please note that I originally wrote this to illustrate the technique rather than having performance in mind. Please also refer to answer @Ivan Krechetov for a more compact solution. Share cultural appropriation of native american